-16x^2+250x-576=0

Solution for -16x^2+250x-576=0 equation:

-16x^2+250x-576=0

a = -16; b = 250; c = -576;
Δ = b2-4ac
Δ = 2502-4·(-16)·(-576)
Δ = 25636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{25636}=\sqrt{4*6409}=\sqrt{4}*\sqrt{6409}=2\sqrt{6409}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(250)-2\sqrt{6409}}{2*-16}=\frac{-250-2\sqrt{6409}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(250)+2\sqrt{6409}}{2*-16}=\frac{-250+2\sqrt{6409}}{-32}
$